where:
- is the initial velocity (20 m/s)
- is the angle of projection (60 degrees)
Plug in the values:
You can evaluate the cosine of 60 degrees, or use the fact that . Therefore:
So, the horizontal component of the velocity of the ball is 10 m/s.
Vx=V⋅cos(θ)
where:
Plug in the values:
Vx=20⋅cos(60∘)
You can evaluate the cosine of 60 degrees, or use the fact that cos(60∘)=21. Therefore:
Vx=20⋅21
Vx=10m/s
So, the horizontal component of the velocity of the ball is 10 m/s.
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