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 The horizontal component of the initial velocity can be found using trigonometry. The horizontal component (Vx) is given by:

��=�⋅cos⁡(�)

where:

  • � is the initial velocity (20 m/s)
  • � is the angle of projection (60 degrees)

Plug in the values:

��=20⋅cos⁡(60∘)

You can evaluate the cosine of 60 degrees, or use the fact that cos⁡(60∘)=12. Therefore:

��=20⋅12

��=10 m/s

So, the horizontal component of the velocity of the ball is 10 m/s.

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