The horizontal component of the initial velocity can be found using trigonometry. The horizontal component (Vx) is given by:

=cos()

where:

  • is the initial velocity (20 m/s)
  • is the angle of projection (60 degrees)

Plug in the values:

=20cos(60)

You can evaluate the cosine of 60 degrees, or use the fact that cos(60)=12. Therefore:

=2012

=10m/s

So, the horizontal component of the velocity of the ball is 10 m/s.

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